SOLUTION: Please solve using the elimination method y = (2/3)x - 1 y = -x + 4 Thank you

Algebra ->  Expressions-with-variables -> SOLUTION: Please solve using the elimination method y = (2/3)x - 1 y = -x + 4 Thank you      Log On


   

Question 1154357: Please solve using the elimination method
y = (2/3)x - 1
y = -x + 4

Thank you
Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

Subtract the first equation from the second equations.


In the left side, "y"s will cancel each other, and you will get an equation for single unknown x


    0 = -x - (2/3)x + 4 - (-1),   

or

    0 = %28-5%2F3%29x+%2B+5.


Multiply both sides by 3 and simplify


    0 = -5x + 15

    5x = 15

     x = 15/5 = 3.


ANSWER.  x = 3;  y = -x + 4 = -3 + 4 = 1.


CHECK.  Make checking on your own, by substituting the found values to the original equations.

Solved.

----------------

About solving systems of linear equations with 2 unknowns by the Elimination or/and Substitution methods, see the lessons
    - Solution of the linear system of two equations in two unknowns by the Substitution method
    - Solution of the linear system of two equations in two unknowns by the Elimination method
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed (i.e. ALWAYS).


Answer by Edwin McCravy(20060) About Me  (Show Source):