Question 1145241: Three boys decide to trade marbles, jacks and checkers. They agree that m marbles can be traded for J jacks, and j jacks for c checkers. What is the number of marbles needed to get C checkers?
Answer by greenestamps(13219)   (Show Source):
You can put this solution on YOUR website!
If C and c are the same, and J and j are the same, then the answer is simple:
c checkers = j jacks = m marbles.
However, since that answer is trivial, and since both C and c, and both J and j, are used in the statement of the problem, I will assume C and c are not necessarily the same, and that J and j are not necessarily the same.
Then the answer can be found by multiplying "C checkers" by unit fractions that change the units without changing the measurement:
j jacks m marbles C*j*m
C checkers * ------------ * ----------- = ------- marbles
c checkers J jacks c*J
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