Question 1107704: At the beginning of a walk, Roberto and Juanita are 5.5
miles apart. If they leave at the same time and walk in the same direction, Roberto overtakes Juanita in 11 hours. If they walk towards each other, they meet in 1 hour. What are their speeds?
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! At the beginning of a walk, Roberto and Juanita are 5.5 miles apart.
If they leave at the same time and walk in the same direction, Roberto overtakes Juanita in 11 hours.
If they walk towards each other, they meet in 1 hour.
What are their speeds?
:
Let r = R's speed
let j = J's speed
:
Write a distance equation for each scenario. dist = time * speed
11(r-j) = 5.5, walking in the same direction
1(r+j) = 5.5, walking towards each other
:
simplify the 1st equation, divide both sides by 11, add to the 2nd equation
r - j = .5
r + j = 5.5
-------------addition eliminates j, find r
2r + 0 = 6.0
r = 6/2
r = 3 mph is R's speed
Find j
3 + j = 5.5
j = 5.5- 3
j = 2.5 mph is J's speed
:
;
Check this in first original equation
11(3 - 2.5) =
11(.5) = 5.5
|
|
|