Question 1077415: Hi there! I am practicing for my math EOC on my own time, and do not understand how to solve this question.
Bill is planning to drive from his house to a baseball stadium and arrive in time for the beginning of the championship game. His arrival time depends on the traffic. If traffic is light, he will travel at an average speed of 50 miles per hour and arrive 1 hour early. If traffic is heavy, he will travel at an average speed of 30 miles per hour and arrive on time. The equation below can be used to model this situation, where t represents Bill’s driving time, in hours.
50(t - 1) = 30t
What is the distance, in miles, from Bill’s house to the baseball stadium?
I got 2.5, but I know that cannot be it because he is driving at average 50 miles per hour. I found this by solving for t.
Please help me! Thanks in advance!!
Found 4 solutions by ikleyn, josgarithmetic, josmiceli, MathTherapy:
Answer by ikleyn(52794)   (Show Source):
You can put this solution on YOUR website! .
Your answer t = 2.5 hour is CORRECT.
It implies that the distance is 30*2.5 = 75 miles.
Check. Time for traveling at 50 mph is  = 1.5 hour.
Time for traveling at 30 mph is  = 2.5 hours.
Correct !!
Answer by josgarithmetic(39618)  (Show Source):
Answer by josmiceli(19441)  (Show Source):
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Hi there! I am practicing for my math EOC on my own time, and do not understand how to solve this question.
Bill is planning to drive from his house to a baseball stadium and arrive in time for the beginning of the championship game. His arrival time depends on the traffic. If traffic is light, he will travel at an average speed of 50 miles per hour and arrive 1 hour early. If traffic is heavy, he will travel at an average speed of 30 miles per hour and arrive on time. The equation below can be used to model this situation, where t represents Bill’s driving time, in hours.
50(t - 1) = 30t
What is the distance, in miles, from Bill’s house to the baseball stadium?
I got 2.5, but I know that cannot be it because he is driving at average 50 miles per hour. I found this by solving for t.
Please help me! Thanks in advance!!
The equation is one of DISTANCE, and is formed so that "t", or the TIME can be determined, based on each speed/rate.
Now, substituting 2.5 for t in the equation results in: 50(2.5 - 1) = 30(2.5), which gives: 50(1.5) = 30(2.5) =====> 75 = 75
Thus, the distance is:
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