Tutors Answer Your Questions about Exponents (FREE)
Question 1186859: The population of a certain inner-city area is estimated to be declining according to the model , where is the number of years from the present. What does this model predict the population will be in years? Round to the nearest person.
Click here to see answer by ikleyn(52776)   |
Question 1188391: Peter and Paul are playing a game involving 60 plastic sticks that are on the table between them. On a turn, a player may remove up to from 1 to 7 sticks from said table. The player that removes the last stick wins. Peter can't guarantee that he'll win the game unless he goes first and removes "k" sticks. The value of "k" is?
a) 1 b) 2 c) 4 d) 6 e) 7
Click here to see answer by Edwin McCravy(20054)  |
Question 1188391: Peter and Paul are playing a game involving 60 plastic sticks that are on the table between them. On a turn, a player may remove up to from 1 to 7 sticks from said table. The player that removes the last stick wins. Peter can't guarantee that he'll win the game unless he goes first and removes "k" sticks. The value of "k" is?
a) 1 b) 2 c) 4 d) 6 e) 7
Click here to see answer by ikleyn(52776) |
Question 1188422: 5^n+2 - 5^n+3 = -2500, My teacher solved it like this. I don't understand why we separate the 5's in the process and where the second 5^n went. Please explain.
5^n x 5^2 - 5^n x 5^3 = -2500
25 x 5^n - 125 x 5^n = -2500
-100 x 5^n = -2500
5^n = 25
5^n = 5^2
n = 2
Click here to see answer by ikleyn(52776) |
Question 1188980: Simplify the following expression. It's the fraction, two-fifths in parenthesis with an exponent of negative 3. The answer in the book is 4/9. I have no clue how they're getting that. Please, help.
.......-3
(2/5)
Click here to see answer by ikleyn(52776) |
Question 1189594: The mass of a substance, which follows a continuous exponential growth model, is being studied in a lab. The doubling time for this substance was observed to be 23 days. There were 72.6 mg of the substance present at the beginning of the study.
(a) Let t be the time (in days) since the beginning of the study, and let
y be the amount of the substance at time t. Write a formula relating y to t. Use exact expressions to fill in the missing parts of the formula. Do not use approximations.
(b) How much will be present in 8 days?
Do not round any intermediate computations, and round your
answer to the nearest tenth.
Click here to see answer by Theo(13342)  |
Question 1189594: The mass of a substance, which follows a continuous exponential growth model, is being studied in a lab. The doubling time for this substance was observed to be 23 days. There were 72.6 mg of the substance present at the beginning of the study.
(a) Let t be the time (in days) since the beginning of the study, and let
y be the amount of the substance at time t. Write a formula relating y to t. Use exact expressions to fill in the missing parts of the formula. Do not use approximations.
(b) How much will be present in 8 days?
Do not round any intermediate computations, and round your
answer to the nearest tenth.
Click here to see answer by ikleyn(52776) |
Question 1190145: Topics In Contemporary Math
Exponential Growth
5)The population of bison was almost hunted to extinction when the United States
expanded westward. The population decreased by 40% per year when the expansion
began in 1803. If the herds of bison originally contained 500,000 bison, how many were
left in 1820?
Click here to see answer by math_tutor2020(3816) |
Question 1190860: Use the given information to find an exponential model of the form Q = Q0e−kt or Q = Q0ekt, as appropriate. Round all numerical values to three significant digits when rounding is necessary.
Q is the amount of radioactive substance with a half-life of 160 years in a sample originally containing 7 grams (t is time in years).
Q =
Click here to see answer by math_tutor2020(3816) |
Question 1190867: A bacteria culture starts with 1,200 bacteria. Two hours later there are 1,800 bacteria. Find an exponential model for the size of the culture as a function of time t in hours.
(a)f(t) =
(b)Use the model to predict how many bacteria there will be after 2 days. (Round your answer to the nearest hundred thousand.)
____bacteria
Click here to see answer by josgarithmetic(39616) |
Question 1192332: Consider the integers m=2^3*3^2*5^3*7^4*11^2*13^5*17^4 and n=2^5*7^8*19^9.
1.) Note that 2^3 is a factor of both m and n. Show that 2^3 is a factor of m+n.
2.) Determine the GCF and LCM of m and n. (explain reasoning)
3.) Show that GCF(m,n) is a factor of LCM(m,n).
Click here to see answer by josgarithmetic(39616) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020
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