Tutors Answer Your Questions about Exponents (FREE)
Question 821446: A math professor purchased a condominium, for $60,000 in 1977. The real estate agent said the value would increase at an annual rate of 7% each year. Assuming the real estate agent was correct, in what year would her condo be worth ten times what she paid for it?
The interest rat is given and so is the increase but, how do I set up an equation to find the year?
Click here to see answer by stanbon(75887)  |
Question 821459: The dosage of a certain drug diminishes in the patient's system exponentially. Based on the results in the table, write an equation and sketch a graph of the function that illustrates the diminishing amount of the drug that remains over time.
Table:
Time (hrs) Amount (mgs)
1 160
3 40
Click here to see answer by KMST(5328)  |
Question 824098: i have two questions one i want too see if I am correct and the other i am struggling with
1. zero as an exponent
(8+5)0 the answer i got is
5+8=13
(13)0
(1)
answer is 1
the question i have is express using negative exponents
1/8=
thank you so much for any help i get
Click here to see answer by Alan3354(69443)  |
Question 824098: i have two questions one i want too see if I am correct and the other i am struggling with
1. zero as an exponent
(8+5)0 the answer i got is
5+8=13
(13)0
(1)
answer is 1
the question i have is express using negative exponents
1/8=
thank you so much for any help i get
Click here to see answer by jim_thompson5910(35256) |
Question 825459: Am solving a 7th grade text book and came across this question.
81^x = 1/(125^y) where x and y are integers. Find 12xy.
The answer given is 0. While I can understand that when x & y are 0 the above equation is satisfied, I can't seem to figure how to arrive at the conclusion.
I tried something like:
--> (3^4x)(5^3y) = 1 --> 3^(4x + 3ky) = 1 where k is such that 3^k = 5 --> 4x + 3ky = 0
But with the above am not able to establish that 12xy is 0.
Please help.
Click here to see answer by unlockmath(1688)  |
Question 825465: I am solving a 7th grade math text book, and I came across this one:
a^x = b^y = c^z, and a³ = b²c, then (3/x) - (2/y) = ?
I tried:
--> c = (a³/b²)
--> a = cube root(b²c)
--> b = √(a³/c),
but couldn't arrive at a conclusion; and also thought there should be a simpler way of solving this.
Please help.
Click here to see answer by jsmallt9(3758) |
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