SOLUTION: How do I solve for A and also B with the following equation? (5x^4)(4x^2)=Ax^b My quess A= (5x^4)(4x^2)/x^b so.. A=20x^6/x^b so.. A=20x^(6+b) (Is this answer correct?)

Algebra ->  Exponents -> SOLUTION: How do I solve for A and also B with the following equation? (5x^4)(4x^2)=Ax^b My quess A= (5x^4)(4x^2)/x^b so.. A=20x^6/x^b so.. A=20x^(6+b) (Is this answer correct?)       Log On


   

Question 97152: How do I solve for A and also B with the following equation?
(5x^4)(4x^2)=Ax^b
My quess
A= (5x^4)(4x^2)/x^b so..
A=20x^6/x^b so..
A=20x^(6+b) (Is this answer correct?)
B= I don't know how to solve this.
Answer by mathslover(157) About Me  (Show Source):
You can put this solution on YOUR website!
Given
+%285x%5E4%29%284x%5E2%29 = Ax%5Eb
applying the law of indices x%5Em+%2A+x%5En = x%5E%28m%2Bn%29
+20+x%5E6 = Ax%5Eb
Equate the coefficients on both sides
20= A
Equating the powers on both sides
6=B
A=20
B=6