You can put this solution on YOUR website! a. f(0) = 6 [all the terms containing an x are canceled out]
b. f(2) = 3(2)^5 - 5(2)^3 + 2(2)^2 + 6
= 3(32) - 5(8) + 2(4) + 6
= 96 - 40 + 8 + 6
= 70
c. f(-2) = 3(-2)^5 - 5(-2)^3 + 2(-2)^2 + 6
= 3(-32) - 5(-8) + 2(4) + 6
= -96 + 40 + 8 + 6
= -42
d. f(2x) = 3(2x)^5 - 5(2x)^3 + 2(2x)^2 + 6
= 3(32x^5) - 5(8x^3) + 2(4x^2) + 6
= 96x^5 - 40x^3 + 8x^2 + 6
[it is not possible to give a numerical answer for this one unless you have a specific value of x to plug in]
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