SOLUTION: Topic:factors and multiples Qn) when 2power256 is divided by 17 the remainder would be?{how to know remAinders and last digits....please help}

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Question 772479: Topic:factors and multiples
Qn) when 2power256 is divided by 17 the remainder would be?{how to know remAinders and last digits....please help}
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
You are most likely asking for %28256%5E2%29%2F17.
65536%2F17
Using ordinary long division, the whole number part of quotient is 3855 and what remains is 1. As a decimal form for the quotient, 1/17=0.05588235294117647..., and those same decimals INCLUDING the zero repeat. If you need to see the long division work for this, then say this.

NOTE:
Note that you asked, "how to know remainders and last digits?"
This looks like a question of the decimal part of the remainder, which is 1%2F17. You DIVIDE 1 by 17, and since this IS RATIONAL, you continue the division process until you find the group of digits repeating. There seem to be 17 arranged digits that repeat, so you would keep doing seventeen decimal places in the long division process for the remainder of 1/17 in order to find the full digitized remainder.


Did you really want %282%5E256%29%2F17 ?
This would be an extremely large number and probably not what you are asking.