SOLUTION: # If x^2+y^2=24 and xy=7 than solve for (x+y)^2 Solution :: We know that (x+y)^2 = x^2 + 2xy + y^2 thErEforE , wE gEt (x+y)^2 = 24 + 2*7 = 38

Algebra ->  Exponents -> SOLUTION: # If x^2+y^2=24 and xy=7 than solve for (x+y)^2 Solution :: We know that (x+y)^2 = x^2 + 2xy + y^2 thErEforE , wE gEt (x+y)^2 = 24 + 2*7 = 38      Log On


   

Question 724530: # If x^2+y^2=24 and xy=7 than solve for (x+y)^2
Solution ::
We know that
(x+y)^2 = x^2 + 2xy + y^2
thErEforE , wE gEt
(x+y)^2 = 24 + 2*7 = 38
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# If x^2+y^2=24 and xy=7 than solve for (x+y)^2
Solution ::
We know that
(x+y)^2 = x^2 + 2xy + y^2
thErEforE , wE gEt
(x+y)^2 = 24 + 2*7 = 38