SOLUTION: how do i work out this equation 4√3:(b)+5=√3:(b)-1 i got as far as converting the cube root to 4(b^1/3)+5=(b^1/3)-1 then i got stuck i tired it on jmy calcullator and

Algebra ->  Exponents -> SOLUTION: how do i work out this equation 4√3:(b)+5=√3:(b)-1 i got as far as converting the cube root to 4(b^1/3)+5=(b^1/3)-1 then i got stuck i tired it on jmy calcullator and       Log On


   

Question 703560: how do i work out this equation 4√3:(b)+5=√3:(b)-1 i got as far as converting the cube root to 4(b^1/3)+5=(b^1/3)-1 then i got stuck i tired it on jmy calcullator and got b=8 not sure how thou
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
4√3:(b)+5=√3:(b)-1
:
I'm going to write it like this, the cube roots are like terms so we can combine
4%2A3sqrt%28b%29%2B5+=+3sqrt%28b%29-1
4%2A3sqrt%28b%29-+3sqrt%28b%29=+-1+-+5
3%2A3sqrt%28b%29+=+-6
divide both sides by 3
3sqrt%28b%29+=+-2
Cube both sides
b = -8
:
:
See if that checks out on a calc; enter
4(-8^(1/3)) + 5 = -3
and
-8^(1/3) - 1 = -3; equality reigns, so a good solution