SOLUTION: in my text book it is written that the expression {{{sqrt 7x}}} is a linear polynomial with degree 1
but my doubt is that how is this possible
according to my doubt {{{sqrt 7
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-> SOLUTION: in my text book it is written that the expression {{{sqrt 7x}}} is a linear polynomial with degree 1
but my doubt is that how is this possible
according to my doubt {{{sqrt 7
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Question 665004: in my text book it is written that the expression is a linear polynomial with degree 1
but my doubt is that how is this possible
according to my doubt is not a linear polynomial as this expression is having a sqrt in the variable. if an expression is having sqrt then its power will be negative. according to the the definition of polynomials there shoud'nt be a negative integral exponent for variables. so is not a polynomial.if it is not a polynomial we cant call it as a linear polynomial.this is my statement
then how is that in the book(maths grade 8 oxford) it is mentioned is a linear polynomial with degree 1. pls explain me Answer by KMST(5330) (Show Source):
You can put this solution on YOUR website! Maybe there was a typo in your textbook.
I have seen errors in high school textbooks, and some online material has even more errors.
To make the meaning clear, you need some brackets.
To write a square root on this website, you need to put whatever is inside that square root in brackets.
sqrt(7x)==(7x)^(1/2)=7^(1/2)x^(1/2) is not a linear polynomial with degree 1. The exponent on the variable is .
sqrt(7)x= is a linear polynomial with degree 1, because the square root only covers the , forming a coefficient in front of the variable , and the variable's exponent is an implied 1.
