SOLUTION: Solve x in the following exponential notation {{{9^(x-1) * 81^(2x-1)=27^(3x-2)}}}

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Question 641767: Solve x in the following exponential notation 9%5E%28x-1%29+%2A+81%5E%282x-1%29=27%5E%283x-2%29
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve x in the following exponential notation 9%5E%28x-1%29+%2A+81%5E%282x-1%29=27%5E%283x-2%29
9^(x-1) * 81^(2x-1)=27^(3x-2)
change to base 3
3^2(x-1)*3^4(2x-1)=3^3(3x-2)
3^(2x-2)*3^(8x-4)=3^(9x-6)
3^[(2x-2)+(8x-4])=3^(9x-6)
3^(10x-6)=3^(9x-6)
10x-6=9x-6
x=0
check:
9^-1*81^-1=27^-2
1/9*1/81=1/27^2
1/729=1/729