SOLUTION: 9^(x-1)*81^(2x-1) =27^(3x-2)

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Question 641762: 9^(x-1)*81^(2x-1) =27^(3x-2)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
9%5E%28x-1%29%2A81%5E%282x-1%29+=+27%5E%283x-2%29
First, find the common base, that's 3:
%283%5E2%29%5E%28x-1%29%2A%283%5E4%29%5E%282x-1%29+=+%283%5E3%29%5E%283x-2%29 Simplify:
3%5E%282x-2%29%2A3%5E%288x-4%29+=+3%5E%289x-6%29 Simplify more:
3%5E%2810x-6%29+=+3%5E%289x-6%29 Now since the bases are equal, the exponents must be equal, so...
10x-6+=+9x-6 Solve for x:
x-6+=+-6
highlight%28x+=+0%29