SOLUTION: Expand {{{(2x - y)^6}}} I was able to expand to: {{{1(2x^6-y^0) + 6(2x^5-y^1) + 15(2x^4-y^2) + 20(2x^3-y^3) + 15(2x^2-y^4) + 6(2x^1-y^5) + 1(2x^0-y^6)}}} I multiplied the

Algebra ->  Exponents -> SOLUTION: Expand {{{(2x - y)^6}}} I was able to expand to: {{{1(2x^6-y^0) + 6(2x^5-y^1) + 15(2x^4-y^2) + 20(2x^3-y^3) + 15(2x^2-y^4) + 6(2x^1-y^5) + 1(2x^0-y^6)}}} I multiplied the       Log On


   



Question 375956: Expand %282x+-+y%29%5E6
I was able to expand to:

I multiplied the coefficients through and got:

Is this the complete expansion?
Thanks for your time!

Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Expand %282x+-+y%29%5E6
You didn't raise the coefficient 2
= 64y^6 - 192x^5y ....

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!


%282x-y%29%5E6 Start with the given expression

To expand this, we're going to use binomial expansion. So let's look at Pascal's triangle:
1   

1   1   

1   2   1   

1   3   3   1   

1   4   6   4   1   

1   5   10   10   5   1   

1   6   15   20   15   6   1   




Looking at the row that starts with 1,6, etc, we can see that this row has the numbers:

1, 6, 15, 20, 15, 6, and 1

These numbers will be the coefficients of our expansion. So to expand %282x-y%29%5E6, simply follow this procedure:
Write the first coefficient. Multiply that coefficient with the first binomial term 2x and then the second binomial term -y. Repeat this until all of the coefficients have been written.

Once that has been done, add up the terms like this:


Notice how the coefficients are in front of each term.



However, we're not done yet.


Looking at the first term 1%282x%29%28-y%29, raise 2x to the 6th power and raise -y to the 0th power.

Looking at the second term 6%282x%29%28-y%29 raise 2x to the 5th power and raise -y to the 1st power.

Continue this until you reach the final term.


Notice how the exponents of 2x are stepping down and the exponents of -y are stepping up.


So the fully expanded expression should now look like this:





Distribute the exponents


Multiply


64x%5E6-192x%5E5y%2B240x%5E4y%5E2-160x%5E3y%5E3%2B60x%5E2y%5E4-12xy%5E5%2By%5E6 Multiply the terms with their coefficients


So %282x-y%29%5E6 expands and simplifies to 64x%5E6-192x%5E5y%2B240x%5E4y%5E2-160x%5E3y%5E3%2B60x%5E2y%5E4-12xy%5E5%2By%5E6.


In other words,


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim