SOLUTION: (3+4i)(1-2i)
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Question 244809
:
(3+4i)(1-2i)
Found 2 solutions by
richwmiller, MathTherapy
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Answer by
richwmiller(17219)
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(3+4i)(1-2i)
remember that i=sqrt(-1)and that i^2=-1
use foil
first term 3*1=3
outer terms 3*2i=6i
inner terms 1*4i=4i
add (6+4)(i)=10i
last terms 4i*2i=8(-1)=-8
3+10i-8
10i-5
Answer by
MathTherapy(10551)
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(3+4i)(1-2i)
Foil the binomials:
F ------- 3 * 1 = 3
O ------- - 2i * + 3 = - 6i
I ------- + 4i * 1 = + 4i
L ------- + 4i * - 2i =
= - 8(-1) = + 8
Putting them together, we get: 3 - 6i + 4i + 8
Combining like terms gives us: