SOLUTION: I have to quick questions on exponents I basically have to simplify them 1. [(9a^3)/(10b^4)]^-2 I came up with: (9^-2*a^3*-2)/(10^-2b^4*-2) (81a^6)/(100b^8) Is that simpl

Algebra ->  Exponents -> SOLUTION: I have to quick questions on exponents I basically have to simplify them 1. [(9a^3)/(10b^4)]^-2 I came up with: (9^-2*a^3*-2)/(10^-2b^4*-2) (81a^6)/(100b^8) Is that simpl      Log On


   

Question 202539: I have to quick questions on exponents
I basically have to simplify them
1. [(9a^3)/(10b^4)]^-2
I came up with:
(9^-2*a^3*-2)/(10^-2b^4*-2)
(81a^6)/(100b^8)
Is that simplified or is there more to do?
2.(6x^5y^2z^-4)(4x^-2y^4z^-1)
I got= 6x^5y^2z^-4/4x^-2y^4z^-1
Am I suppose to flip the equation to get rid of the negative exponents are do I just add them together they way they are?
(u^5z^8)/(z^-5u^-4)
In this one too I flip the equation to: Z^5u^4/u^5z^8 and i got u^9z^13
Was I suppose to flip it?


Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify:
1. %28%289a%5E3%29%2F%2810b%5E4%29%29%5E-2+=+%28%2810b%5E4%29%2F%289a%5E3%29%29%5E2=highlight%28%28100b%5E8%29%2F%2881a%5E6%29%29
2. %286x%5E5y%5E2z%5E-4%29%284x%5E-2y%5E4z%5E-1%29 For each variable (x, y, and z), multiply their coefficients and add their exponents.
24x%5E3y%5E6z%5E-5 Now make the z-exponent positive by moving it to the denominator.
highlight%28%2824x%5E3y%5E6%29%2Fz%5E5%29
3. %28u%5E5z%5E8%29%2F%28z%5E-5u%5E-4%29 For each variable (u and z) subtract their exponents.
%28u%5E%285-%28-5%29%29z%5E%288-%28-4%29%29%29 Simplify.
highlight%28u%5E10z%5E12%29