SOLUTION: 2xsquared-12xy-32ysquared

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Question 186892: 2xsquared-12xy-32ysquared
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming that you want to factor.



2x%5E2-12xy-32y%5E2 Start with the given expression


2%28x%5E2-6xy-16y%5E2%29 Factor out the GCF 2


Now let's focus on the inner expression x%5E2-6xy-16y%5E2




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Looking at x%5E2-6xy-16y%5E2 we can see that the first term is x%5E2 and the last term is -16y%5E2 where the coefficients are 1 and -16 respectively.

Now multiply the first coefficient 1 and the last coefficient -16 to get -16. Now what two numbers multiply to -16 and add to the middle coefficient -6? Let's list all of the factors of -16:



Factors of -16:
1,2,4,8

-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -16
(1)*(-16)
(2)*(-8)
(-1)*(16)
(-2)*(8)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to -6? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -6

First NumberSecond NumberSum
1-161+(-16)=-15
2-82+(-8)=-6
-116-1+16=15
-28-2+8=6



From this list we can see that 2 and -8 add up to -6 and multiply to -16


Now looking at the expression x%5E2-6xy-16y%5E2, replace -6xy with 2xy-8xy (notice 2xy-8xy combines to -6xy. So it is equivalent to -6xy)


x%5E2%2Bhighlight%282xy-8xy%29%2B-16y%5E2


Now let's factor 1x%5E2%2B2xy-8xy-16y%5E2 by grouping:


%28x%5E2%2B2xy%29%2B%28-8xy-16y%5E2%29 Group like terms


x%28x%2B2y%29-8y%28x%2B2y%29 Factor out the GCF of x out of the first group. Factor out the GCF of -8y out of the second group


%28x-8y%29%28x%2B2y%29 Since we have a common term of x%2B2y, we can combine like terms


So x%5E2%2B2xy-8xy-16y%5E2 factors to %28x-8y%29%28x%2B2y%29


So this also means that x%5E2-6xy-16y%5E2 factors to %28x-8y%29%28x%2B2y%29 (since x%5E2-6xy-16y%5E2 is equivalent to x%5E2%2B2xy-8xy-16y%5E2)



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So our expression goes from 2%28x%5E2-6xy-16y%5E2%29 and factors further to 2%28x-8y%29%28x%2B2y%29


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Answer:

So 2x%5E2-12xy-32y%5E2 factors to 2%28x-8y%29%28x%2B2y%29