SOLUTION: How do you solve for y in the equation (y^2=y+30)?

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Question 172893This question is from textbook geometry
: How do you solve for y in the equation (y^2=y+30)? This question is from textbook geometry

Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve for y in the equation (y^2=y+30)?
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y^2=y+30 Get the zero on the right side
y^2 - y - 30 = 0
(y-6)*(y+5) = 0
One of the binomials has to be zero if the product is zero.
y = 6
y = -5

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
The same way you would solve any quadratic.

First put it in standard form: y%5E2-y-30=0

Fortunately, this one factors because -6%2A5=30 and -6%2B5=-1, so

%28y-6%29%28y%2B5%29=0

y-6=0 => y=6
or
y%2B5=0 => y=-5