SOLUTION: Solve 3^2x-1=27

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Question 1210583: Solve 3^2x-1=27
Answer by math_tutor2020(3835) About Me  (Show Source):
You can put this solution on YOUR website!

If the equation is 3%5E%282x-1%29+=+27 then we can rewrite 27 as 3%5E3 to arrive at 3%5E%282x-1%29+=+3%5E3

Each base is the same (3), so the exponents must be equal in order for the original equation to be valid.

Once you arrive at 2x-1+=+3 it should be fairly easy to solve. I'll let the student take over from here.