SOLUTION: What is z to the zero power times z to the negative 10th? Only using positive exponents.

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Question 1190689: What is z to the zero power times z to the negative 10th? Only using positive exponents.
Found 2 solutions by math_tutor2020, Alan3354:
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

Any nonzero number to the exponent of 0 will result in 1.
z%5E0+=+1 as long as z+%3C%3E+0
Multiplying by 1 has no effect, so the z^0 won't affect the answer.

The z%5E%28-10%29 portion then turns into 1%2F%28z%5E%2810%29%29 when we make the exponent positive. Take the reciprocal of the base to make the exponent positive.
The general rule is that a%5E%28-b%29+=+1%2F%28a%5Eb%29 or you can think of it like %28a%2Fb%29%5E%28-c%29+=+%28b%2Fa%29%5Ec

Answer: 1%2F%28z%5E%2810%29%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
0^0 = 1, by convention.
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That means some people made that decision.
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In 1752, Euler in Introductio in analysin infinitorum wrote that a0 = 1[15] and explicitly mentioned that 0^0 = 1.[16] An annotation attributed[17] to Mascheroni in a 1787 edition of Euler's book Institutiones calculi differentialis[18] offered the "justification"
{\displaystyle 0^{0}=(a-a)^{n-n}={\frac {(a-a)^{n}}{(a-a)^{n}}}=1}{\displaystyle 0^{0}=(a-a)^{n-n}={\frac {(a-a)^{n}}{(a-a)^{n}}}=1}
as well as another more involved justification. In the 1830s, Libri[19][17] published several further arguments attempting to justify the claim 0^0 = 1, though these were far from convincing, even by standards of rigor at the time.[20]
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I wouldn't argue with Euler.