Question 1184060: Solve the initial value problem yy′+x=√x^2+y^2 with y(1)=√3
a)To solve this, we should use the substitution
u= My answer is y/x , wrong.
u′= My answer is (xy'-y)/x^2 , wrong.
Enter derivatives using prime notation (e.g., you would enter y′ for dy/dx).
b)After the substitution from the previous part, we obtain the following linear differential equation in x,u,u′.
My answer is xu'+u=(sqrt(1+u^2)-1)/u , wrong.
c)The solution to the original initial value problem is described by the following equation in x,y.
My answer is sqrt(x^2+y^2)-x=1 , wrong.
Answer by robertb(5830)   (Show Source):
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