SOLUTION: The sum of 128 consecutive odd, positive integers is the greatest power of two less than 200,000. The sum of the least and the greatest of these integers is 2^N. What is the value

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Question 1168309: The sum of 128 consecutive odd, positive integers is the greatest power of two less than 200,000. The sum of the least and the greatest of these integers is 2^N. What is the value of N?
Answer by ikleyn(52787) About Me  (Show Source):
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The sum of 128 consecutive odd, positive integers is the greatest power of two less than 200,000.
The sum of the least and the greatest of these integers is 2^N. What is the value of N?
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log%282%2C+%28200000%29%29 = 17.61 (approximately, with two decimals).


Therefore, the greatest power of 2 less than 200,000 is  2%5E17 = 131072.


So, the sum of 128 consecutive odd positive integers is  131072.


These consecutive integer numbers form an arithmetic progression;

therefore, their sum is the product of the number of terms (128) by half the sum of the least and the greatest of these two numbers.


In other words,  2%5E17 = 128%2A%281%2F2%29%2A2%5EN.


It is equivalent to


    2%5E17 = 2%5E7%2A2%5E%28-1%29%2A2%5EN,  or

    2%5E17 = 2%5E%287-1%2BN%29,       or

    2%5E17 = 2%5E%28N%2B6%29.


It implies  17 = N + 6,  or  N = 17 - 6 = 11.


ANSWER.  N = 11.

Solved.