SOLUTION: State both real values of x that satisfy the equation [(3x+4)/(5x+1)]^2+(3x+4)/(5x+1)=12

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Question 1096721: State both real values of x that satisfy the equation [(3x+4)/(5x+1)]^2+(3x+4)/(5x+1)=12
Answer by ikleyn(52750) About Me  (Show Source):
You can put this solution on YOUR website!
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highlight%28cross%28State%29%29 Find highlight%28cross%28both%29%29 all real values of x that satisfy the equation [(3x+4)/(5x+1)]^2+(3x+4)/(5x+1)=12
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%28%283x%2B4%29%2F%285x%2B1%29%29%5E2 + %283x%2B4%29%2F%285x%2B1%29 = 12.


Introduce new variable u = %283x%2B4%29%2F%285x%2B1%29.  Then your equation becomes this quadratic equation

u%5E2+%2B+u+-+12 = 0.


Factor left side polynomial. You will get

(u+4)*(u-3) = 0,

which has two roots  u= -4  and  u= 3.


a)  Case u= -4:  then  %283x%2B4%29%2F%285x%2B1%29 = -4  ====>  3x+4 = (-4)*(5x+1)  ====>  3x+4 = -20x-4  ====>  23x = -8  ====>  x = -8%2F23.


b)  Case u= 3:   then  %283x%2B4%29%2F%285x%2B1%29 = 3  ====>  3x+4 = 3*(5x+1)  ====>  3x+4 = 15x+3  ====>  12x = 1  ====>  x = 1%2F12.


Answer.  The original equation has two solutions  x= -8%2F23  and  x= 1%2F12.

Introducing new variable is a standard method of solution non-linear equations like this one.