Tutors Answer Your Questions about Exponents-negative-and-fractional (FREE)
Question 849508: To convert from square meters, multiply by -6.452 X 10^-4. Suppose that the area if the square is 6X10^-4 square inches. Convert this area to square meters. (Use scientific notation)
3.87 X 10 ^-07 is wrong
Please help!
Thank you
Click here to see answer by richwmiller(17219)   |
Question 849508: To convert from square meters, multiply by -6.452 X 10^-4. Suppose that the area if the square is 6X10^-4 square inches. Convert this area to square meters. (Use scientific notation)
3.87 X 10 ^-07 is wrong
Please help!
Thank you
Click here to see answer by ewatrrr(24785)  |
Question 852048: I have a reliability related question.
I wish to transpose the reliability formula r= e^-lambda t to make t the subject. Where e is exponential log raised to the power of minus lambda times t.
I wish to know t= what?
Click here to see answer by Fombitz(32388)  |
Question 853803: Hello..
I need help with the following question to see if I have done it correctly.
The question is as follows:
"Simplify the following:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^2 y^4 (x-1)^-2 z^-1"
the / is obviously "divided by"..
My answer is written this way:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^2 y^4 (x-1)^-2 z^-1
= 3^-2 (x-1)^4 x^3 y^6 z^5 9^-2 x^-12 y^14 (x-1)^2 z^1
= 1/9 (x-1)^2 x^-9 y^2 z^4 1/81
That is my final answer. I don't know how to attach images otherwise I would do that to make reading the question and answer properly...
Can someone please let me know if I have done it correctly and if I haven't, can you please show me how to do it?
Thank-you very much,
zeedee
Click here to see answer by Fombitz(32388) |
Question 855760: Hello..
I need help with the following question to see if I have done it correctly.
The question is as follows:
"Simplify the following:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1"
the / is obviously "divided by"..
My answer is written this way:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1
= 1/9 (x-1)^4 x^3 y^6 z^5 / 3x^3 y^4 (x-1)^-2 z^-1
= 1/9.3 (x-1)^4 (x-1)^2 x^3 x^-3 y^6 y^-4 z^5 z^1
= 1/3 (x-1)^6 x^0 y^2 z^6
= (x-1)^6 y^2 z^6 / 3
Can someone please let me know if I have done it correctly and if I haven't, can you please show me how to do it?
Thank-you very much,
zeedee
Click here to see answer by Alan3354(69443)  |
Question 876431: 27 ^ -2/3
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27 ^ -1/3
This is what I have done:
I moved the bottom expression to the top. Then take the LCD of 6, which changes the expressions to 27 ^ -4/6 + 27 ^ -2/6. Add the two expressions which gives me 27 ^ -6/6. Then to eliminate negative exponent, expression is put under 1.....like this
1
------------
27 ^ 6/6
Final answer is
1
-----------
27
I'm not sure, please help me
Click here to see answer by jim_thompson5910(35256) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330
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