Tutors Answer Your Questions about Exponents-negative-and-fractional (FREE)
Question 677206: Can someone check my work please? I feel like I'm missing steps. I'm not sure if I'm on the right track with this one. Thank you!
[3y^(2/3)]^(-3)
(3y(2/3))^-3 =
(6y/3)^-3 =
(2y)^-3 = 2^-3y^-3 = 1/(2^3y^3)=1/8y^3
Click here to see answer by Alan3354(69443)  |
Question 677757: The first 10 Fibonacci numbers are 1, 1, 2, 3, 5, 8, 13, 21, 34, 55. If the ith Fibonacci number is denoted ƒi, calculate:
5
SIGMA SIGN f2j
j=3
I appologize, the sigma sign cannot be cut and pasted...
Click here to see answer by jim_thompson5910(35256) |
Question 677750: I appologize in advance for the way this problem is typed, the square root sign cannot be cut & pasted.
solve:
zx^-4 (sqrt)X (yz^4)^3
/ DIVIDED BY
Z^7xy
I came up with a horrible answer, 2916. My math work must have gone wrong some where?
Click here to see answer by MathLover1(20850)  |
Question 686266: -32 ^ (-6/5): To make the exponent positive, we write expression in the denominator, getting 1/-32^6/5. Then, the fifth root of -32 is -2, and -2 raised to the sixth power equals positive 64. So the answer seems to be 1/64. Yet the answer provided is -(1/64). Why? Thank you very much for your help.
Click here to see answer by nerdybill(7384)  |
Question 688858: I am working on a math page. It says: Lorenzo needed to find 1/9 of 27. His friend Carla told him to write 1/9 as 3 to the -2 and 27 as 3 to the 3 to get 3 to the negative 6. Was Carla correct? Explain.
I think she's correct, but I'm not quite sure on how to explain it.
Click here to see answer by Alan3354(69443)  |
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