Tutors Answer Your Questions about Exponents-negative-and-fractional (FREE)
Question 515210: This is hard for me to type out so I hope that it makes sense. I am struggling with this and for some reason I cannot figure out this one problem. Thank you in advance!
(-7xy^-3)^-4 then there is the bar and on the bottom of the bar it's (xy^-3)^-9
I really hope this makes sense.. It is -7xy to the negative 3 and then exponent on outside of parentheses is a -4. Then on the bottom it says xy to the negative 3rd and then outside of parantheses exponent is negative 9. Thanks so much!
Click here to see answer by mananth(16946)   |
Question 516766: Hello,
My son is in 7th grade pre-algebra. We are trying to find what "negative two-thirds times two equals". He then must label a graph with this point. Normaly we would turn this fraction into a decimal. 2 divided by 3 equals ? Then times 2. But I do not understand the negative and the answer we're getting will not work on the graph. I would really appreciate your help if I've given you enough information. Thank you, Andy
Click here to see answer by Earlsdon(6294) |
Question 523689: i have been working on "i exponent 1/2" for a while.
i think it is 0.5i since...
rewrite as "i^1 over 2"
remove the "exponent 1"
"i over 2" is the same as 0.5i
my problem is that i need to begin with an "a+bi" format then raise both sides to remove the exponent. then i should be left with an answer.
thank you
Click here to see answer by richard1234(7193)  |
Question 525757: 3 to the 4th power = 27 to the m-2 power.
What is m?
I made the 27 = to 3 to the third power and multiplied the 3(m-2). I then set that equal to 4. 4=3(m-2) It doesn't seem right because then m=3 1/3 which means it would be 27 to the 4/3 power. Is that possible?
Click here to see answer by solver91311(24713)  |
Question 539739: a^-2-2a^-1+5=0
I have tried this problem several times and am stuck. I can tell you I put the negatives on the bottom and came up with a common demoninator but I still can not come up with the correct answer.
Click here to see answer by mananth(16946) |
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