Tutors Answer Your Questions about Exponents-negative-and-fractional (FREE)
Question 341826: This problem involves factoring terms that include positive and negative exponents. For some reason I just can't see it:
(3x+2)(2/3)(6x-5)^(-1/3)(6)+(6x-5)^(2/3)(3)
I keep coming up with:
I factored out (6x-5)^(-1/3)(2/3)(3)[(3x+2)+2(6x-5)^(3/3) <- (or 1)
So that simplifies to: (6x-5)^(-1/3)(2)(3x+2)+12x-10
Further simplified to: (6x-5)^(-1/3)[6x+4+12x-10]
The (6x-5)^(-1/3) moves to the denominator and 18x-6 remains in the numerator.
I don't know where I am going wrong with this. I know the denominator is right, but the answer shown for the numerator is 30x-7 and I just can't figure out how to get to that.
Click here to see answer by stanbon(75887) |
Question 352103: Hello!
My problem is finding all real solutions with the following equation 
I put 6 on the other side so it turns into

I can't combine the two terms so I ended up subtracting -5x^(2/3) from both sides to get:

Then I will take the power 3/4th to both sides so X on the left is by itself.

Which will simplify to:

This is where I get stuck.
I have a feeling I screwed up somewhere.
Can you please help me?
Thank you.
-Kayte.
Click here to see answer by Fombitz(32388)  |
Question 352103: Hello!
My problem is finding all real solutions with the following equation 
I put 6 on the other side so it turns into

I can't combine the two terms so I ended up subtracting -5x^(2/3) from both sides to get:

Then I will take the power 3/4th to both sides so X on the left is by itself.

Which will simplify to:

This is where I get stuck.
I have a feeling I screwed up somewhere.
Can you please help me?
Thank you.
-Kayte.
Click here to see answer by stanbon(75887) |
Question 352106: I have to find all real solutions for the following equation: 
I converted the into 
So the equation turned into:

Then I distributed x^2 on one side and ^3/2 on the other. So I get:

The x and 3x can simplify to 4x. and I move this over into the other side.

I feel like I can somehow turn this into a quadratic formula, but unsure how.
So here is where I'm stuck.
Thank you!
-Kayte
Click here to see answer by stanbon(75887) |
Question 353521: The bread that lynn is baking requires 4 1/2 cups of flour. she has 1 3/4 cups of flour in a canister aand 1/8 cup of flour in a measuring cup. How much more flour does she need to have enough flour to bake the bread?
Click here to see answer by mananth(16946)  |
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