SOLUTION: calculate!!! {{{ (2^n+2^(n-1))/(2^(n+1)-2^n) }}}.

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: calculate!!! {{{ (2^n+2^(n-1))/(2^(n+1)-2^n) }}}.      Log On


   

Question 95898: calculate!!!
+%282%5En%2B2%5E%28n-1%29%29%2F%282%5E%28n%2B1%29-2%5En%29+.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(2^n + 2^(n-1)) / (2^(n+1) - 2^n)
Factor to get:
[2^(n-1)(2+1)] / [2^n(2-1)]
Simplify:
[2(n-1)(3)] / [2^n]

= 3/2
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Cheers,
Stan H.