SOLUTION: If 5x-3 < or = 5 + 3x < or =4x + 2 express it as a< or = x < or = b and then the values of a & b

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: If 5x-3 < or = 5 + 3x < or =4x + 2 express it as a< or = x < or = b and then the values of a & b      Log On


   

Question 947682: If 5x-3 < or = 5 + 3x < or =4x + 2 express it as a< or = x < or = b and then the values of a & b
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
5x-3 < or = 5 + 3x < or =4x + 2
5x-3<=5+3x<=4x+2
5x-3%3C=5%2B3x%3C=4x%2B2


You may already know the properties to use. That extended inequality is two inequalities
combined with AND.

highlight_green%285x-3%3C=5%2B3x%29
5x-3x-3%3C=5
2x-3%3C=5
2x%3C=5%2B3
2x%3C=8
highlight%28x%3C=4%29

AND

highlight_green%285%2B3x%3C=4x%2B2%29
4x%2B2%3E=5%2B3x
4x%2B2-3x%3E=5
x%2B2%3E=5
x%3E=5-2
highlight%28x%3E=3%29


Put both results together.
highlight%28highlight%283%3C=x%3C=4%29%29