SOLUTION: 3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: 3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5      Log On


   

Question 93708: 3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
Answer by jayanthihemkos@yahoo.com(87) About Me  (Show Source):
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3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
==>3(5-2(-1)2-1) -3(2+4(2)-8+3(-3)+1-2)1-3)+4-5
==>3(5-4(-1)-1)-3(2+8-8-9+1-2)1-3)+4-5
==>3(5+4-1) -3(-8)1-3)+4-5
==>3(8)-3(-8)-3)+4-5
==>24+24-3+4-5
==>52-8
==>44