SOLUTION: Please help solve this equation: (4x^-2 y^1/3)^3/2

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: Please help solve this equation: (4x^-2 y^1/3)^3/2       Log On


   

Question 936890: Please help solve this equation: (4x^-2 y^1/3)^3/2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
a%5E0+=+1
%28+x%5Em+%29%28+x%5En+%29+=+x%5E%28+m+%2B+n+%29
x%5Em%2Fx%5En=x%5E%28m-n%29
%28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29 ***
%28xy%29%5En+=+x%5En%2Ay%5En
x^(1/n) = root%28n%2Cx%29
x^(m/n) = root%28n%2Cx%5Em%29***
.........
(4^1x^-2^1y^1/3)^3/2 = 4^(3/2)x^(-3) - 2^(3/2)y^(1/2) = 8/x^3 - 2√2√y
........
4^(3/2) = root%282%2C4%5E3%29 = 8
2^(3/2) = root%282%2C2%5E3%29+=+sqrt%288%29 = 2√2