SOLUTION: can someone please tell me if i did this right? i had to write in the simplest form without negative exponents. [(-2)^-2]^-3 = -2^6 therefore i had gotten 64 as my answer.

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: can someone please tell me if i did this right? i had to write in the simplest form without negative exponents. [(-2)^-2]^-3 = -2^6 therefore i had gotten 64 as my answer.      Log On


   

Question 91854This question is from textbook algebra and trigonometry
: can someone please tell me if i did this right? i had to write in the simplest form without negative exponents. [(-2)^-2]^-3 = -2^6 therefore i had gotten 64 as my answer. This question is from textbook algebra and trigonometry

Answer by homeworkhelpanytime(21) About Me  (Show Source):
You can put this solution on YOUR website!
[(-2)^-2]^-3
= [(-1/2)^2]^-3
= [1/4]^-3
= (4)^3
=64
your answer is correct