You can put this solution on YOUR website! Find the. Equation of the graph with following points. (-2;0) (3;0) (0;3)
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y=ax^2+bx+c
(-2,0) ... 0=4a-2b+c
(3,0)...... 0=9a+3b+c
(0,3)......3=0+0+c
..
c=3
4a-2b+3=0
9a+3b+3=0
..
12a-6b+9=0
18a+6b+6=0
30a+15=0
30a=-15
a=-1/2
2b=4a+3
2b=-2+3=1
b=1/2
check:
4a-2b+c=-2-1+3=0
9a+3b+c=-9/2+3/2+3=0
equation: (-1/2)x^2+(1/2)x+3=0
-x^2/2+x/2+3=0
see graph below:
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