SOLUTION: O.k the problems are:(-7)to the power of 5 times (-7) times the power of -2. It said on the worksheet to wite the product without exponents. How can you solve it?
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-> SOLUTION: O.k the problems are:(-7)to the power of 5 times (-7) times the power of -2. It said on the worksheet to wite the product without exponents. How can you solve it?
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Question 67146This question is from textbook punchline: bridge to algebra
: O.k the problems are:(-7)to the power of 5 times (-7) times the power of -2. It said on the worksheet to wite the product without exponents. How can you solve it? This question is from textbook punchline: bridge to algebra
You can put this solution on YOUR website! O.k the problems are:(-7)to the power of 5 times (-7) times the power of -2. It said on the worksheet to wite the product without exponents. How can you solve it?
((-7)^5)((-7)^-2)
Lets first look at each term separately:
(-7)^5=-7*-7*-7*-7*-7
(-7)^-2=1/(-7^2)=1/(-7*-7)
((-7)^5)((-7)^-2)=(7*-7*-7*-7*-7)(1/(-7*-7) when we cancel the 7's, we will have 3 sevens left in the numerator:
((-7)^5)((-7)^-2)=-7^3=-7*-7*-7
Multiply -7*-7*-7 =49*-7=-343
Another way to look at it:
When you multiply, you add exponents, so:
((-7)^5)((-7)^-2)=((-7)^(5-2))=(-7)^3=-343
