SOLUTION: please help me solve this: 7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power. I know the answer is 1, but do not know how to get to that an

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: please help me solve this: 7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power. I know the answer is 1, but do not know how to get to that an      Log On


   

Question 658689: please help me solve this: 7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power. I know the answer is 1, but do not know how to get
to that answer.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
(7^-4)^-2 = 7^(-4*-2) = 7^8

(7^4)^-2 = 7^(4*-2) = 7^-8

So "7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power" becomes 7%5E8%2A7%5E%28-8%29+=+7%5E%288%2B%28-8%29%29+=+7%5E0+=+1