SOLUTION: Add. Express your answer in simplest form. x-13 + 3x-3 ---- ----- x^2-x-12 x^2-x-12 the denominator is the same, so I'm sure this is simple and I am mak

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: Add. Express your answer in simplest form. x-13 + 3x-3 ---- ----- x^2-x-12 x^2-x-12 the denominator is the same, so I'm sure this is simple and I am mak      Log On


   

Question 62693This question is from textbook Beginning Algebra
: Add. Express your answer in simplest form.
x-13 + 3x-3
---- -----
x^2-x-12 x^2-x-12
the denominator is the same, so I'm sure this is simple and I am making harder than it is. This question is from textbook Beginning Algebra

Found 2 solutions by stanbon, Cintchr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x-13 + 3x-3
---- -----
x^2-x-12 x^2-x-12
---------------------------
The denominators are the same, so add the numerators, as follows:
----------
[4x-16]/[x^2-x-12]
=[4(x-4)]/[(x-4)(x+3)]
Cancel the (x-4) factors to get:
=4/(x+3)
---------
Cheers,
Stan H.

Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+%28x-13%29%2F%28x%5E2-x-12%29+%2B+%283x-3%29%2F%28x%5E2-x-12%29+
Make it into one fraction
+%28x-13%2B3x-3%29%2F%28x%5E2-x-12%29+
Combine like terms in the numerator
+%284x+-16%29%2F%28x%5E2-x-12%29+
factor numerator and denominator
+4%28x-4%29%2F%28x-4%29%28x%2B3%29+
Reduce the fraction
+4%2F%28x%2B3%29+