SOLUTION: If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the r

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the r      Log On


   



Question 257521: If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!

P=2L+2W
22=2L+2W
P=a+b+c
12=L/2+W+5
22=2L+2W
L=8 and W=3