SOLUTION: can you please help me determine how many x-intercepts the parabola has and wether its vertex lies above or below or on the x-axis ((( y=x^2-5x+6 )))
{{{y=x^2-5x+6}}}------(1)
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-> SOLUTION: can you please help me determine how many x-intercepts the parabola has and wether its vertex lies above or below or on the x-axis ((( y=x^2-5x+6 )))
{{{y=x^2-5x+6}}}------(1)
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Question 198266This question is from textbook algebra sturcture and method
: can you please help me determine how many x-intercepts the parabola has and wether its vertex lies above or below or on the x-axis ((( y=x^2-5x+6 )))
------(1)
x intercept ==> y=0. So put y=0 in (1)
==>
==>
==> x={2,3}
So the parabola have two x intercepts.
Since the sign of x^2 is positive, the parabola has a minimum at its vertex.
Vertex is [-b/2a,f(-b/2a)]= (5/2,-1/4) So the vertex lies below the x axis. This question is from textbook algebra sturcture and method
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