SOLUTION: (y^4)^-2(2x^4y^-2)^3 divided by (4x^-7y^-2)^2

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Question 180230: (y^4)^-2(2x^4y^-2)^3 divided by (4x^-7y^-2)^2
Answer by eperette(173) About Me  (Show Source):
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(y^4)^-2(2x^4y^-2)^3 divided by (4x^-7y^-2)^2
(y^4*-2)(2^3)(x^4*3)(y^-2*3) divided by (4^2)(x^-7*2)(y^-2*2)
(y^-8)(8)(x^12)(y^-6) divided by (16)(x^-14)(y^-4)
8(y^-8+-6)(x^12) divided by 16(x^-14)(y^-4)
8y^-14x^12 divided by 16x^-14y^-4
8/16 (y^-14--4)(x^12--14)
1/2(y^-14+4)(x^12+14)
1/2(y^-10)(x^26)
(x^26)/(2y^10)