SOLUTION: Can you help with my Algebra problems? Q#15 {{{a^(n)/3b^(m)=b^3/3}}} Q#29 {{{6a^-1c^-3/d^0}}}

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Question 176834This question is from textbook Tennessee Prentice Hall Mathematics Algebra I
: Can you help with my Algebra problems?

Q#15 a%5E%28n%29%2F3b%5E%28m%29=b%5E3%2F3
Q#29 6a%5E-1c%5E-3%2Fd%5E0
Q#30 2%5E-3x%5E2z%5E-7
Q#327s%5E0t%5E-5%2F2%5E-1m%5E2
This question is from textbook Tennessee Prentice Hall Mathematics Algebra I

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Anything raised to the zero power is 1 a%5E0+=+1 for all a. A negative exponent means take the reciprocal, that is: a%5E%28-n%29=1%2Fa%5En, in other words, move the variable from denominator to numerator or from numerator to denominator and change the sign.

So for your first problem, in order for the a term to go away and remain non-zero, the exponent on a has to be 1, so you can say right off that n=1. The b variable is in the denominator in the left hand fraction and in the numerator in the right hand fraction. That means the 3 exponent on b on the right must have been -3 on the left. m=+-3.

You should be able to handle the rest of them by applying the same principles.