SOLUTION: Simplify (6ab^4c/5b^3c^2)^3 I know when dividing you subtract the expoents, i just don't know how to set the problem up.

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Question 148985This question is from textbook
: Simplify (6ab^4c/5b^3c^2)^3
I know when dividing you subtract the expoents, i just don't know how to set the problem up. This question is from textbook

Found 2 solutions by stanbon, mangopeeler07:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify (6ab^4c/5b^3c^2)^3
= (6ab/5c)^3
= (216a^3b^3/125c^3)
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Cheers,
Stan H.

Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
(6ab^4c/5b^3c^2)^3 Once you set it up like this, simplify it by dividing (as you said, subtracting exponents). Then cube the result (the cube transfers to everything, coefficients and variables).

In the end, you should get:
%28216%28a%5E3%29%28b%5E3%29%29%2F125c%5E3