SOLUTION: evaluating indices (216/27) to the power of -2/3

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: evaluating indices (216/27) to the power of -2/3      Log On


   

Question 129679: evaluating indices (216/27) to the power of -2/3
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(216/27) to the power of -2/3
---------------
(216/27)^(-2/3)
The negative means "invert"
You get:
(27/216)^(2/3)
The 3 means"take the cube root"
You get:
(3/6)^2
The 2 means "square.
(1/2)^2 = 1/4
=================
Cheers,
Stan H.