SOLUTION: Please help me answer this question:
{{{(1/8)-2/3}}}
I started this:
(1/8)-2/3 = 1/(1/8)-2/3) = 1 x (8/1)-2/3 this is where I get stuck.
Thanks.
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: Please help me answer this question:
{{{(1/8)-2/3}}}
I started this:
(1/8)-2/3 = 1/(1/8)-2/3) = 1 x (8/1)-2/3 this is where I get stuck.
Thanks.
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Question 121726: Please help me answer this question:
I started this:
(1/8)-2/3 = 1/(1/8)-2/3) = 1 x (8/1)-2/3 this is where I get stuck.
Thanks. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Your problem is either subtracting fractions or taking fractions to a fractional power.
We can look at both.
Subtractng fractions.
Whenever you add or subtract fractions you need to have the same denominator.
The easiest way to get a common denominator is to make it the product of your two denominators.
Now find each fraction as an equivalent fraction with denominator of 24.
and
Now you can subtract.
Taking fractions to a fractional power.
You can also look at 1/8 as .
From your exponentiation rules,
Then