SOLUTION: how do I figure out 2x^-3*y^-2/z^4
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Question 121593
:
how do I figure out 2x^-3*y^-2/z^4
Answer by
stanbon(75887)
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2x^-3*y^-2/z^4
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Usually the text will ask you to express this
without negative exponents:
= (2/x^3)(1/(y^2*z^4)
= 2/[x^3*y^2*z^4]
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Cheers,
Stan H.