SOLUTION: Write 6.92 x 10 to the -5 power in standard form.

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Question 116569: Write 6.92 x 10 to the -5 power in standard form.
Found 3 solutions by MathLover1, bucky, Edwin McCravy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

6.92+%2A+10+%5E-5+………you can write this like;
6.92+%281%2F10+%5E5%29+=+6.92+%281%2F100000%29+=+6.92%2A0.00001=+0.0000692+………

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given 6.92 x 10^(-5)
.
The negative sign on the exponent of 10 tells you that the decimal point is to be moved 5 places
to the LEFT.
.
So there needs to be 4 zeros between the decimal point and the 6.
.
The answer is 0.0000692
.
You might also think of the problem this way:
.
Since the given exponent on 10 is negative, you know the decimal point needs to move to the
left.
.
Write 6.92 with a bunch of zeros in front of it:
.
0000000006.92
.
Now start moving the decimal point to the left the number of places equal to the number in
the exponent of 10. In this case you will move 5 places total. The first place to the left
will be between the last zero and the 6. Then move to the left four more places and get the
answer of 0.0000692. Note that for decimals of this type it is customary to leave one
zero to the left of the decimal ... just to highlight that there is a decimal point.
.
Hope this gives you just a little more understanding of scientific notation.
.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Write 6.92 x 10 to the -5 power in standard form.

When you see

DECIMAL x 10±INTEGER EXPONENT

1. If the INTEGER EXPONENT is POSITIVE, move the decimal point the
same number of places to the RIGHT as as the INTEGER EXPONENT. Then
erase the "×10INTEGER EXPONENT"
This may involve annexing some 0's on the RIGHT.

2. If the INTEGER EXPONENT is NEGATIVE, move the decimal point the
same number of places to the LEFT as as the absolute value of the
INTEGER EXPONENT. Then erase the "×10±INTEGER EXPONENT"
This may involve annexing some 0's on the LEFT.

Your problem is 6.92 × 10-5, the integer exponent is
NEGATIVE so case 2 applies.

So we need to move the decimal point of 6.92 five places to the 
LEFT.  But first we must annex enough 0's on the left so that we
can move it that many places.  So we write:

000006.92 × 10-5 

Then we move the decimal point 5 places left, getting

0.0000692 × 10-5

and erasing the "× 10-5"

or

0.0000692

Edwin