SOLUTION: Please help me solve -5/2 - (-2/9)

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Question 1144456: Please help me solve
-5/2 - (-2/9)

Found 4 solutions by josgarithmetic, MathTherapy, ikleyn, Alan3354:
Answer by josgarithmetic(39623) About Me  (Show Source):
Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Please help me solve
-5/2 - (-2/9)
Student, DON'T accept that answer from that dude, It's WRONG, as usual. matrix%281%2C4%2C+-+5%2F2+-+%28-+2%2F9%29%2C+DOES%2C+NOT%2C+%22=%22+-+2%29. 
You should be able to see this LOGIC: matrix%281%2C3%2C+-+5%2F2%2C+%22=%22%2C+-+2%261%2F2%29, and the ONLY way that simplifies to - 2 is to ADD matrix%281%2C3%2C+1%2F2%2C+to%2C+-+2%261%2F2%29. Is matrix%281%2C3%2C+-+-+2%2F9%2C+%22=%22%2C+1%2F2%29?
He needs to just give it up and QUIT trying to help, because the only help he gives is ALMOST ALWAYS MISLEADING, and/or SENSELESS.

Answer by ikleyn(52831) About Me  (Show Source):
You can put this solution on YOUR website!
.

-5/2 - (-2/9) = -5%2F2 - %28-2%2F9%29 = -5%2F2+%2B+2%2F9 = 


                    write with the common denominator, which is 18


              = %28-5%2A9%29%2F%282%2A9%29 + %282%2A2%29%2F%282%2A9%29 = -45%2F18 + 4%2F18%29 = %28-45%2B4%29%2F18 = -41%2F18.    ANSWER

The rules are:


(1)  ADDING       a%2Fb + c%2Fd = 

                       you can work with the common denominator.
                       you also can take the product of the denominators - it works, too

                  = %28a%2Ad%29%2F%28b%2Ad%29 + %28c%2Ab%29%2F%28b%2Ad%29 = %28ad+%2B+bc%29%2Fbd.


(2)  SUBTRACTING  a%2Fb - c%2Fd = 

                       you can work with the common denominator.
                       you also can take the product of the denominators - it works, too

                  = %28a%2Ad%29%2F%28b%2Ad%29 - %28c%2Ab%29%2F%28b%2Ad%29 = %28ad+-+bc%29%2Fbd.


You may solve  ALL  your problems  ON  YOUR  OWN,  by knowing and using these simple rules.

OK,  if not all,  then at least half of your problems.

If you want to learn this simple algebra  (sorry,  arithmetic),  then you must do these simple steps on your own.

In this site,  we do not teach from scratch - we are not a school.
We assume that the students come here just having basic knowledge and elementary skills.
In particular,  we assume that you just are able to add and subtract fractions.


/\/\/\/\/\/\/\/

    This quasi- and pseudo-tutor @josgaritmetic placed totally incorrect solution in his post.

    The tutor @MathTherapy noticed it, and then I placed a correct solution.

    After that @josgarithmetic quickly re-wrote from my post, without acknowledgement (of course). 

    It is not something EXTRAORDINARY - he does it EVERY day.

    As a tutor, he equals to zero and have no any relevant qualification.

    If you are new at this forum, you should know it.

    Be aware :  every second - third - fourth his "solution" is INCORRECT.


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Equations are solved.
Equations have equal signs.
---> this is not an equation, nothing to solve.
It's arithmetic.