SOLUTION: {{{ 6ax^4/14x^2y^2 }}} x {{{ 2y^3/3a^4 }}} I understand from the book I have that when simplified you get the followin results: {{{x^2/7}}} x {{{2y/a^3}}} = {{{2x^2y/7a^3}}} I unde
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: {{{ 6ax^4/14x^2y^2 }}} x {{{ 2y^3/3a^4 }}} I understand from the book I have that when simplified you get the followin results: {{{x^2/7}}} x {{{2y/a^3}}} = {{{2x^2y/7a^3}}} I unde
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Question 106245This question is from textbook teach yourself algebra
: x I understand from the book I have that when simplified you get the followin results: x = I understand how the letters are cancelled out what I do not understand is why the numbers6 and 3 disappear, the 14 halves to 7 and the 2 does not change? Pleae could you help me? This question is from textbook teach yourself algebra
