SOLUTION: The book is not making any sense to me, please help! Perform the long division and write the partial fraction decomposition of the remainder term. (x^4 - x^2 + 2)/(x^3 - x^2)

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: The book is not making any sense to me, please help! Perform the long division and write the partial fraction decomposition of the remainder term. (x^4 - x^2 + 2)/(x^3 - x^2)      Log On


   



Question 1042243: The book is not making any sense to me, please help!
Perform the long division and write the partial fraction decomposition of the remainder term.
(x^4 - x^2 + 2)/(x^3 - x^2)

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

%28x%5E4+-+x%5E2+%2B+2%29%2F%28x%5E3+-+x%5E2%29

Put in zero placeholders for missing powers of x

%28x%5E4+%2B0x%5E3-+x%5E2+%2B0x%2B+2%29%2F%28x%5E3+-+x%5E2%2B0x%2B0%29

                       x+1
x³-x²+0x+0)x⁴+0x³- x²+0x+2
           x⁴- x³+0x²+0x
               x³- x²+0x+2
               x³- x²+0x+0
                  0x²+0x+2

So 

%28x%5E4+-+x%5E2+%2B+2%29%2F%28x%5E3+-+x%5E2%29%22%22=%22%22x%2B1%2B2%2F%28x%5E3-x%5E2%29%22%22=%22%22

x%2B1+%2B+2%5E%22%22%2F%28x%5E2%28x-1%29%29%22%22=%22%22x%2B1%2BA%5E%22%22%2Fx%5E%22%22%2BB%5E%22%22%2Fx%5E2%2BC%5E%22%22%2F%28x-1%29%5E%22%22

Just taking the fraction parts:

2%2F%28x%5E2%28x-1%29%29%22%22=%22%22A%5E%22%22%2Fx%5E%22%22%2BB%5E%22%22%2Fx%5E2%2BC%5E%22%22%2F%28x-1%29%5E%22%22

Multiply through by the LCD = x²(x-1)

2%22%22=%22%22Ax%28x-1%29%2BB%28x-1%29%2BCx%5E2

If we let x=0, 2 terms on the right will become 0:

2%22%22=%22%22A%2A0%280-1%29%2BB%280-1%29%2BC%2A0%5E2

2%22%22=%22%22-B

B%22%22=%22%22-2, substituting:

2%22%22=%22%22Ax%28x-1%29-2%28x-1%29%2BCx%5E2

If we let x=1, 2 terms on the right will become 0

2%22%22=%22%22A%2A1%281-1%29-2%281-1%29%2BC%2A1%5E2

2%22%22=%22%22A%280%29-2%280%29%2BC%2A1

2%22%22=%22%22C, substituting:

2%22%22=%22%22Ax%28x-1%29-2%28x-1%29%2B2x%5E2

Now we can let x be any number, say choose easy x=2

2%22%22=%22%22A%2A2%282-1%29-2%282-1%29%2B2%2A2%5E2

2%22%22=%22%22A%2A2%281%29-2%281%29%2B2%2A4

2%22%22=%22%222A-2%2B8

2%22%22=%22%222A%2B6

-4%22%22=%22%222A

-2%22%22=%22%22A, 

substitute A=-2, B=-2, and C=2 in

%28x%5E4+-+x%5E2+%2B+2%29%2F%28x%5E3+-+x%5E2%29%22%22=%22%22x%2B1+%2B+%28x%5E2%2B2%29%2F%28x%5E2%28x-1%29%29%22%22=%22%22x%2B1%2BA%5E%22%22%2Fx%5E%22%22%2BB%5E%22%22%2Fx%5E2%2BC%5E%22%22%2F%28x-1%29%5E%22%22%22%22=%22%22

x%2B1-2%5E%22%22%2Fx%5E%22%22-2%5E%22%22%2Fx%5E2%2B2%5E%22%22%2F%28x-1%29%5E%22%22

Edwin