SOLUTION: {{{(3x^3)/(x^3+27) - x/(x+3) + (2x^2)/(x^2-3x+9)}}}
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Exponents-negative-and-fractional
-> SOLUTION: {{{(3x^3)/(x^3+27) - x/(x+3) + (2x^2)/(x^2-3x+9)}}}
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Algebra: Negative and Fractional exponents
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Question 103968
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Answer by
jim_thompson5910(35256)
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Start with the given expression
Factor
into
So this means the LCM is
(since every denominator has either
,
, or both). So we want every fraction to have a denominator of
Multiply the second fraction by
Multiply
Distribute
Multiply the third fraction by
Multiply
Distribute
Since we have a common denominator, we can combine the fractions
Combine the fractions
Distribute the negative
Combine like terms
Factor the numerator
Cancel like terms
Simplify
Factor out an x
So
simplifies to